Someone tells you that it is possible to make any number by writing an addition sum using only consecutive numbers Essays

Somebody reveals to you that it is conceivable to make any number by composing an expansion whole utilizing just back to back numbers Essays Somebody reveals to you that it is conceivable to make any number by composing an expansion whole utilizing just back to back numbers Essay Somebody reveals to you that it is conceivable to make any number by composing an expansion aggregate utilizing just continuous numbers Essay 18 = 3 + 4 + 5 + 6 6 = 1 + 2 + 3 21 = 1 + 2 + 3 + 4 + 5 + 6 An) Is this individual right? B) Can you make each number? C) Investigate and record everything that you notice, as you come. (For example designs) ____________________________________________ A) This individual must not be right as they said you could make any number and I can't cause 8,16,32,40,56,64,80,88,96 this isn't any number I to feel this is adequate evidence to state that you can not make any number. B) You can not make each number as a ton of numbers in the multiple times table can not be made, for example, 8,16,32,40,56,64,80,88,96 so only one out of every odd number can be made. C) 1 CON NUMBERS 2 CON NUMBERS 3 CON NUMBERS 4 CON NUMBERS 5 CON NUMBERS 1 0 + 1 2 3 1+2 0+1+2 4 5 2+3 6 1+2+3 0+1+2+3 7 3+4 8 ** ** ** ** ** 9 4+5 2+3+4 10 1+2+3+4 11 5+6 0+1+2+3+4+5 12 3+4+5 13 6+7 14 2+3+4+5 15 7+8 4+5+6 1+2+3+4+5 16 ** ** ** ** ** 17 8+9 18 5+6+7 3+4+5+6 19 9+10 20 2+3+4+5+6 21 10+11 6+7+8 22 4+5+6+7 23 11+12 24 7+8+9 25 12+13 3+4+5+6+7 26 5+6+7+8 27 13+14 8+9+10 28 ** ** ** ** ** 29 14+15 30 9+10+11 6+7+8+9 4+5+6+7+8 I have seen there is an equivalent hole each time. The more back to back numbers the greater the hole between each aggregate. For example 2 Consecutive Numbers I saw that these back to back numbers are for the most part odd numbers 3,5,7,9,11.I likewise saw that a Nth expression could be found. For example 1 2 3 4 5 3 5 7 9 11 2 Nth term = 2n 100th term = 2 x 100 + 1= 201 I need the third term I realize that the term will be 7 however I have to ensure my hypothesis works. For example 1 2 3 4 5 3 5 7 9 11 2 Nth term = 2n third term = 2 x 3 + 1=7 3 Consecutive Numbers I am going to attempt to discover the nth term for 3 back to back numbers. For example 1 2 3 4 5 6 9 12 15 18 3 Nth term = 3n 100th term = 3100 + 3=303 Again to demonstrate this is correct I will work out the third term. Nth term =3n third term = 3 x 3 + 3 =12 I have demonstrated that my hypothesis works. 4 Consecutive Numbers Presently I am going to locate the Nth expression for four back to back numbers. For example 1 2 3 4 5 6 10 14 18 22 4 Nth term = 4n 100th term = 4 x 100 + 2 = 402 Presently again I should test my hypothesis. Nth term = 4n third term =4 x 3 + 2 = 14 I have now demonstrated that hypothesis is right I can discover any term which 4 continuous numbers make. 5 Consecutive Numbers Presently I am going to discover the Nth expression for 5 successive numbers. 1 2 3 4 5 11 15 20 25 30 5 Nth term = 5n 100th term = 5 x 100 + 5 = 505 Presently I should ensure it works. Nth term = 5n third term = 5 x 3 + 5 = 20 The hypothesis is correct I would now be able to discover any term, which is made by 5 back to back numbers.